![]() In a specific example for the Model MR50-12, the accuracy becomes ☐.55% x 135 Ncm = ☐.7425 Ncm. Using the example of a Series R50 torque sensor with Model 3i indicator, add ☐.35% to ☐.2%, which equals ☐.55%. Models 7i and 5i indicators have accuracy values of ☐.1% FS, while the Model 3i is rated at ☐.2% FS. The accuracies of the sensor and the indicator must be added together. Example 2 – Plug & Test ® indicators and sensors: ![]() For example, if the displayed value is 30.00 lbF, the true reading will be ≥29.95 lbF and ≤30.05 lbF. This means that any displayed reading may be higher or lower by up to 0.05 lbF. Multiply ☐.1% by 50 lbF, which equals ☐.05 lbF. To determine the measurement error as an actual load value, multiply the accuracy percentage by the instrument’s capacity. Mark-10 defines accuracy as a percentage of full scale of the instrument.
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